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Sic Bo Results

 

The Mathematics of Sic Bo

By

Michael Shackleford

Sic Bo is an ancient Chinese game that is played with three dice. You will find Sic Bo in land-based and online casinos all over the world. Live Sic Bo is a live dealer offering of the dice game that has been growing in popularity over the years. Live Sic Bo is going to be one of the more difficult live dealer games to find though, so don’t expect to see it everywhere. Take a change and win a change. To make more money with high winning rates. Sulive betting - Sweet moffo, Roulette, sports betting, Slots, Virtual quick win. A sic bo cheat sheet is a way to map out strategy and odds of how bet. You can line up the different combinations of how the die combine. Each of these combinations has three different permutations except the first triple one combination.

Example of the layout of a Sic Bo table It is easy to see why Sic Bo and Craps are compared, but Sic Bo is strictly a game of chance as every roll of the dice results in a win or loss of the bet as opposed to Craps which has some bets that need certain rolls before the outcome is known therefore adding an element of skill and strategy to it.

January 21, 2005

Sic Bo, meaning 'dice pair' is an ancient Chinese gambling game. Today it is one of the lesser known casino games and is often confined to designated rooms for Asian games. The game uses three dice and a table with a variety of betting options on the roll of those dice. The odds and table layout may also vary from place to place. If you must play Sic Bo I would suggest sticking to only the 'low' and 'high' bets.


Images taken from the Claridge Hotel/Casino rule book.
Results

Following is a list of the bets available. The payoffs listed are for Atlantic City and the Mirage in Las Vegas. Other casino’s odds will vary.

  • Small: Wins on total of 4-10, except for a three of a kind. Pays 1 to 1.
  • Big: Wins on total of 11-17, except for a three of a kind. Pays 1 to 1.
  • 4: Wins on total of 4. Pays 60 to 1.
  • 5: Wins on total of 5. Pays 30 to 1.
  • 6: Wins on total of 6. Pays 17 to 1.
  • 7: Wins on total of 7. Pays 12 to 1.
  • 8: Wins on total of 8. Pays 8 to 1.
  • 9: Wins on total of 9. Pays 6 to 1.
  • 10: Wins on total of 10. Pays 6 to 1.
  • 11: Wins on total of 11. Pays 6 to 1.
  • 12: Wins on total of 12. Pays 6 to 1.
  • 13: Wins on total of 13. Pays 8 to 1.
  • 14: Wins on total of 14. Pays 12 to 1.
  • 15: Wins on total of 15. Pays 17 to 1.
  • 16: Wins on total of 16. Pays 30 to 1.
  • 17: Wins on total of 17. Pays 60 to 1.
  • Two of a kind: Player may bet on any of the 15 possible two dice combinations (for example a 1 and 2). Bet wins if both numbers appear. Probability of winning is 13.89%. Pays 5 to 1.
  • Double: Player may bet on any specific number (for example a 1). Player wins if at least 2 of the 3 dice land on that number. Probability of winning is 7.41%. Pays 10 to 1.
  • Triple: Player may bet on any specific number (for example a 1). Player wins if all 3 dice land on that number. Probability of winning is 0.46%. Pays 180 to 1.
  • Any Triple: Wins on any three of a kind. Pays 30 to 1.
  • Individual Number: Player may bet on any specific number from 1 to 6. If chosen number appears 1 time bet pays 1 to 1, if it appears 2 times bet pays 2 to 1, and if it appears 3 times it pays 3 to 1.

The critical step in calculating the odds in Sic Bo is to find the probability of any given total in the throw of three dice. Following is a formula for s spots over n dice, taken from The Theory of Gambling and Statistical Logic by Richard A. Epstein, formula 5-14.

For example, let's look at the number of ways to get 11 spots over 3 dice.

int[(s-n)/6] = int[(11-3)/6] = int[1.33] = 1

The total would be 6-3 * [-10*combin(3,0)*combin(11-6*0-1,3-1) + -11*combin(3,1)*combin(11-6*1-1,3-1) ] =
1/218 * [1*1*combin(10,2) + -1*3*combin(4,2)] =
1/218 * [1*1*45 + -1*3*6] =
1/218 * [45-18] = 27/216 = 12.50%

Alternatively, if you can program a computer that would probably be the fastest way to get the results.

Here is a simple function in C++.

Following is the output of the function.

Total

Permutations

Probability

3

1

0.00463

4

3

0.013889

5

6

0.027778

6

10

0.046296

7

15

0.069444

8

21

0.097222

9

25

0.115741

10

27

0.125

11

27

0.125

12

25

0.115741

13

21

0.097222

14

15

0.069444

15

10

0.046296

16

6

0.027778

17

3

0.013889

18

1

0.00463

If you don’t know how to program you’re going to have to do this the hard way. What I recommend is list every combination of 3 dice. To avoid the list being 63=216 items long do not repeat the same combinations in different orders. In the interests of not listing the same number twice always order each combination from lowest to highest, not forgetting combinations with a pair or three of a kind.

So we start with 1,1,1.

Next would be 1,1,2.

Then 1,1,3; 1,1,4; 1,1,5; and 1,1,6.

Obviously you can’t roll a 7 with one dice so next we increment the second die.

1,2,?

The third die must be greater or equal to the second die so the next combination in full would be 1,2,2.

Next comes 1,2,3; 1,2,4; 1,2,5; and 1,2,6.

Then comes 1,3,3.

I hope you see the pattern. The whole list would look like the following.

Low die

Medium Die

High Die

1

1

1

1

1

2

1

1

3

1

1

4

1

1

5

1

1

6

1

2

2

1

2

3

1

2

4

1

2

5

1

2

6

1

3

3

1

3

4

1

3

5

1

3

6

1

4

4

1

4

5

1

4

6

1

5

5

1

5

6

1

6

6

2

2

2

2

2

3

2

2

4

2

2

5

2

2

6

2

3

3

2

3

4

2

3

5

2

3

6

2

4

4

2

4

5

2

4

6

2

5

5

2

5

6

2

6

6

3

3

3

3

3

4

3

3

5

3

3

6

3

4

4

3

4

5

3

4

6

3

5

5

3

5

6

3

6

6

4

4

4

4

4

5

4

4

6

4

5

5

4

5

6

4

6

6

5

5

5

5

5

6

5

6

6

6

6

6

Next we have to determine the number of permutations of each combination. A combination is a set without regard to order and a permutation is a set with regard to order.

With a three of a kind there is only one way permutation. For example if the three dice are 1,1,1 there is only one way to roll that a 1 each time.

If the combination is 1,1,2 there are three ways to roll that: 1,1,2; 1,2,1; and 2,1,1.

If all three dice are 1,2,3 there are six possible permutations: 1,2,3; 1,3,2; 2,1,3; 2,3,1; 3,1,2; 3,2,1

The general formula is that if you have a total of d dice and the totals of each number are x1, x2, x3…xn then the number of permutations are d!/(x1!*x2!*x3*…*xn). So the number of ways to get a three of a kind would be 3!/3! = 6/6 = 1. The number of ways to get a pair would be 3!/(2!*1!) = 6/(2*1) = 3. The number of ways to get three different numbers would be 3!/(1!*1!*1!) = 6/(1*1*1) = 6.

Low die

Medium die

High die

Total

Permutations

1

1

1

3

1

1

1

2

4

3

1

1

3

5

3

1

1

4

6

3

1

1

5

7

3

1

1

6

8

3

1

2

2

5

3

1

2

3

6

6

1

2

4

7

6

1

2

5

8

6

1

2

6

9

6

1

3

3

7

3

1

3

4

8

6

1

3

5

9

6

1

3

6

10

6

1

4

4

9

3

1

4

5

10

6

1

4

6

11

6

1

5

5

11

3

1

5

6

12

6

1

6

6

13

3

2

2

2

6

1

2

2

3

7

3

2

2

4

8

3

2

2

5

9

3

2

2

6

10

3

2

3

3

8

3

2

3

4

9

6

2

3

5

10

6

2

3

6

11

6

2

4

4

10

3

2

4

5

11

6

2

4

6

12

6

2

5

5

12

3

2

5

6

13

6

2

6

6

14

3

3

3

3

9

1

3

3

4

10

3

3

3

5

11

3

3

3

6

12

3

3

4

4

11

3

3

4

5

12

6

3

4

6

13

6

3

5

5

13

3

3

5

6

14

6

3

6

6

15

3

4

4

4

12

1

4

4

5

13

3

4

4

6

14

3

4

5

5

14

3

4

5

6

15

6

4

6

6

16

3

5

5

5

15

1

5

5

6

16

3

5

6

6

17

3

6

6

6

18

1

Total

216

Next we go through the tedious process of adding the number of permutations for each total. For example a total of 6 has the following combinations with the corresponding number of permutations.

Combinations

Number of Permutations

1,1,4

3

1,2,3

6

2,2,2

1

Total

10

The final table will look like this, not unlike the result of the computer function earlier.

So now lets add a column to our list for the number of combinations of each set. Let’s also add a total for the three dice.

Total

Permutations

3

1

4

3

5

6

6

10

7

15

8

21

9

25

10

27

11

27

12

25

13

21

14

15

15

10

16

6

17

3

18

1

Total

216

Now we can divide each total number permutations by the total number 3-dice permutations (216) to get the probability of each total.

Total

Permutations

Probability

3

1

0.00463

4

3

0.013889

5

6

0.027778

6

10

0.046296

7

15

0.069444

8

21

0.097222

9

25

0.115741

10

27

0.125

11

27

0.125

12

25

0.115741

13

21

0.097222

14

15

0.069444

15

10

0.046296

16

6

0.027778

17

3

0.013889

18

1

0.00463

Total

216

1

Finally, we are ready to evaluate the expected value of each bet. The expected value is the ratio of the amount the player can expect to win to the amount he bets on any given bet. So a fair bet would an expected value of zero. A positive expected value would mean the player has the advantage. A negative expected value would mean the dealer has the advantage.

Sic Bo Results

Let’s start with the 4 bet. This wins with a total of 4 and pays 60 to 1. For those who don’t know, '60 to 1' means if the player wins he wins 60 times his bet and KEEPS his original wager. Had the odds paid '60 for 1' the player would NOT keep his original bet. Most table games pay on a 'to 1' basis.

The probability of a total of 4 is 3/216 = 0.013889. Thus the probability of losing is 1-(3/216) = 1-0.013889 = 0.986111.

The expected value of any bet with only two possibilities, winning or losing, is:

(Probability of winning)*(Amount of win) + (Probability of losing)*(Amount of loss).

For the 4 bet the expected value is

0.013889 * 60 - 0.986111*-1 = -0.15278.

So, this tells us that for every dollar the player bets on a total of 4 he can expect to lose 15.278 cents on average. Or, the house edge is 15.278%.

The next table shows the expected value and how it was calculated for all bets of a total of 4 to 17.

Total

Pays

Probability of Win

Probability of Losing

Formula of expected value

Expected Value

4

60

0.013889

0.986111

0.0138889*60-0.986111*-1

-0.15278

5

30

0.027778

0.972222

0.0277778*30-0.972222*-1

-0.13889

6

17

0.046296

0.953704

0.0462963*17-0.953704*-1

-0.16667

7

12

0.069444

0.930556

0.0694444*12-0.930556*-1

-0.09722

8

8

0.097222

0.902778

0.0972222*8-0.902778*-1

-0.125

9

6

0.115741

0.884259

0.115741*6-0.884259*-1

-0.18981

10

6

0.125

0.875

0.125*6-0.875*-1

-0.125

11

6

0.125

0.875

0.125*6-0.875*-1

-0.125

12

6

0.115741

0.884259

0.115741*6-0.884259*-1

-0.18981

13

8

0.097222

0.902778

0.0972222*8-0.902778*-1

-0.125

14

12

0.069444

0.930556

0.0694444*12-0.930556*-1

-0.09722

15

17

0.046296

0.953704

0.0462963*17-0.953704*-1

-0.16667

16

30

0.027778

0.972222

0.0277778*30-0.972222*-1

-0.13889

17

60

0.013889

0.986111

0.0138889*60-0.986111*-1

-0.15278

Two of a kind

There are combin(6,2)=6!/(4!*2!)=15 ways to choose two numbers out of six. Each of these combinations is listed on the table and the player bet on as many as he wishes. If both numbers appear on the roll of the three dice then the player wins and is paid 15 to 1.

Let’s assume the player picks a 1 and 2 as his two numbers. What is the probability that both a 1 and 2 occur in the roll of 3 dice? One way to do this would be to note all the possible winning permutations:

Dice

Number of Permutations

1,2,3

6

1,2,4

6

1,2,5

6

1,2,6

6

1,1,2

3

1,2,2

3

Total

30

Thus there are a total of 30 winning permutations.

There are 63=216 total permutations, so the probability of winning is 30/216 = 1/36 = 0.1388889

The two of a kind bet pays 5 to 1. So the expected value is 0.1388889*5 + (1-0.1388889)*-1 = -0.16667. In other words the house edge is 16.67%.

Double

There are six double bets available, one for each number from 1 to 6. The player may be on any one or combination of bets. Any given bet wins if at least two of the three dice land on that number.

Let’s assume the player bets on the 1.

One way to solve it would be to note all the winning permutations:

Dice

Number of Permutations

1,1,2

3

1,1,3

3

1,1,4

3

1,1,5

3

1,1,6

3

1,1,1

1

Total

16

Thus there are a total of 16 winning permutations.

There are 63=216 total permutations, so the probability of winning is 16/216 = 0.0740741.

The double bet pays 10 to 1. So the expected value is 0.0740741*10 + (1-0.0740741)*-1 = -0.18518. In other words the house edge is 18.52% (ouch!).

Triple

Player may bet on any specific number (for example a 1). Player wins if all 3 dice land on that number.

There is obviously only one way to win this bet, so the probability of winning is 1/216 = 0.0046296. The bet pays 180 to 1 so the expected value is 0.0046296*180 + (1-0.0046296)*-1 = -0.16204. So the house edge is 16.204%.

Any Triple

The Any Triple bet pays if any three of a kind is thrown. There are obviously six winning combinations (1,1,1; 2,2,2; 3,3,3; etc.). So the probability of winning is 6/216 = 0.027778. The bet pays 30 to 1 so the expected value is 0.027778*30 + (1-0.027778)*-1 = -0.13889. So the house edge is 13.89%.

Low

The low bet wins if the total of the three dice is 3 to 10, without being a three of a kind. The probability of any total 10 or less is exactly 50%. The average number on any one die is (1+2+3+4+5+6)/6 = 21/6 = 3.5. So the average of three dice is 3*3.5 = 10.5. It stands to reason that the probability of getting under or over 10.5 is 50%.

However the bet loses on a three of a kind. There are 3 three of a kinds that would turn a winner into a loser: 1,1,1; 2,2,2; and 3,3,3. So the probability of having a total of 10 or less as a three of a kind is 3/216 = 0.0188889. So the overall probability of winning is 0.5 – 0.188889 = 0.4861111. The bet pays 1 to 1 so the expected value is 0.4861111*1 + (1-0.4861111)*-1 = -0.02778. Thus the house edge is 2.78%.

High

Sic Bo Results Ufc

The high is just the opposite of the low bet, so it stands to reason the house edge would also be 2.78%.

Individual Number

Player may bet on any specific number from 1 to 6. If chosen number appears 1 time bet pays 1 to 1, if it appears 2 times bet pays 2 to 1, and if it appears 3 times it pays 3 to 1. Probability of 1 match is 34.72%, 2 matches is 6.94%, 3 matches is 0.46%.

Let’s assume the player picks the number one.

There is only one way to get three ones: 1,1,1. So the probability of three ones is 1/63 = 1/216.

Following are the ways to get two 1’s and the number of permutations of each.

Dice

Number of Permutations

1,1,2

3

1,1,3

3

1,1,4

3

1,1,5

3

1,1,6

3

Total

15

So the probability of two ones is 15/63 = 15/216.

Following are the ways to get one 1 and the number of permutations of each.

Dice

Number of Permutations

1,2,2

3

1,2,3

6

1,2,4

6

1,2,5

6

1,2,6

6

1,3,3

3

1,3,4

6

1,3,5

6

1,3,6

6

1,4,4

3

1,4,5

6

1,4,6

6

1,5,5

3

1,5,6

6

1,6,6

3

Total

75

So the probability of two ones is 75/63 = 75/216.

Another way to arrive at the probability of one 1 would be find the probability that the first die is a one and the second and third are not:

Pr(one)*Pr(not one)*Pr(not one) = (1/6)*(5/6)*(5/6) = 25/216.

However the one could appear in the first, second, or third position, so multiply by 3: 3*(25/216) = 75/216.

The probability of rolling zero ones is Pr(not one)*Pr(not one)*Pr(not one) = (5/6)*(5/6)*(5/6) = (5/6)3 = 125/216.

The following return table shows the possible outcomes, and the number of combinations, probability, and return of each. The return is the product of the probability and the win or loss to the player.

Sic Bo Results 2020

Event

Permutations

Probability

Pays

Return

Player rolls 3 ones

1

0.00463

3

0.013889

Player rolls 2 ones

15

0.069444

2

0.138889

Player roll 1 one

75

0.347222

1

0.347222

Player rolls 0 ones

125

0.578704

-1

-0.5787

Total

216

1

-0.0787

So the total expected return is -0.0787, or the house edge is 7.87%.

Sic Bo section at the Wizard of Odds.
How to calcualte the 3-dice permutation in Visual Basic.

The layout of a sic bo table

Sic bo (骰寶), also known as tai sai (大細), dai siu (大小), big and small or hi-lo, is an unequal game of chance of ancient Chinese origin played with three dice. Grand hazard and chuck-a-luck are variants, both of English origin. The literal meaning of sic bo is 'precious dice', while dai siu and dai sai mean 'big [or] small'.

Sic bo is a casino game, popular in Asia and widely played (as dai siu) in casinos in Macau. It is played in the Philippines as hi-lo.[1] It was introduced to the United States by Chinese immigrants in the early 20th century, and can now be found in most American casinos. Since 2002, it can be played legally in licensed casinos in the United Kingdom.

Gameplay involves betting that a certain condition (e.g. that all three dice will roll the same) will be satisfied by a roll of the dice.[2]

Gameplay[edit]

Players place their bets on certain areas of the table as shown in the picture above. The dealer then picks up a small chest containing the dice, which he/she closes and shakes. Finally the dealer opens the chest to reveal the combination. It is important to place the bet at Sic bo in the specified time. Players should also know the minimum and maximum betting amounts for different types of bets at Sic bo.[3]

Comparison to craps[edit]

Sic bo is one of two casino games involving dice, the other being craps. Sic bo is strictly a game of chance because every roll on the dice results a win or loss on any bet. In craps, some bets require certain rolls before they can become winning or losing bets, thus encouraging strategy.

Betting options[edit]

TypeWagerProbabilityUnited KingdomNew ZealandMacauNo House Edge
OddsHouse EdgeOddsHouse EdgeOddsHouse EdgeOdds
Big (大)The total score will be from 11 to 17 (inclusive) with the exception of a triple48.61%1 to 12.78%1 to 12.78%1 to 12.78%37 to 35
Small (小)The total score will be from 4 to 10 (inclusive) with the exception of a triple48.61%1 to 12.78%1 to 12.78%1 to 12.78%37 to 35
OddThe total score will be an odd number with the exception of a triple48.61%1 to 12.78%1 to 12.78%37 to 35
EvenThe total score will be an even number with the exception of a triple48.61%1 to 12.78%1 to 12.78%37 to 35
Specific 'Triples' or 'Alls' (圍一 圍二 圍三 圍四 圍五 圍六)A specific number will appear on all three dice0.46%180 to 116.2%180 to 116.2%150 to 130.1%215 to 1
Specific DoublesA specific number will appear on at least two of the three dice7.41%10 to 118.5%11 to 111.1%8 to 133.3%25 to 2
Any Triple or All 'Alls' (全圍)Any of the triples will appear2.8%30 to 113.9%31 to 111.1%24 to 130.6%35 to 1
Three Dice Total

(a specific total score in the range of 4 to 17 inclusive)

4 or 171.4%60 to 115.3%62 to 112.5%50 to 129.2%71 to 1
5 or 162.8%30 to 113.9%31 to 111.1%18 to 147.2%35 to 1
6 or 154.6%18 to 112%18 to 112%14 to 130.6%103 to 5
7 or 146.9%12 to 19.7%12 to 19.7%12 to 19.7%67 to 5
8 or 139.7%8 to 112.5%8 to 112.5%8 to 112.5%65 to 7
9 or 1211.6%7 to 17.4%7 to 17.4%6 to 119%191 to 25
10 or 1112.5%6 to 112.5%6 to 112.5%6 to 112.5%7 to 1
Dice CombinationsTwo of the dice will show a specific combination of two different numbers (for example, a 3 and a 4)13.9%6 to 12.8%6 to 12.8%5 to 116.7%31 to 5
Single Dice BetThe specific number 1, 2, 3, 4, 5, or 6 will appear on one, two, or all three dice1: 34.72%
2: 6.94%
3: 0.46%
1: 1 to 1
2: 2 to 1
3: 3 to 1
7.9%1: 1 to 1
2: 2 to 1
3: 12 to 1
3.7%1: 1 to 1
2: 2 to 1
3: 3 to 1
7.9%1: 1 to 1
2: 3 to 1
3: 5 to 1 (simplest version)
Four Number CombinationAny three of the four numbers in one of the following specific combinations will appear: 6, 5, 4, 3; 6, 5, 3, 2; 5, 4, 3, 2; or 4, 3, 2, 111.1%7 to 111.1%7 to 111.1%7 to 111.1%8 to 1
Three Single Number CombinationThe dice will show a specific combination of three different numbers2.8%30 to 113.9%30 to 113.9%35 to 1
Specific Double and Single Number CombinationTwo of the dice will show a specific double and the third die will show a specific, different number1.4%50 to 129.2%60 to 115.3%71 to 1

The most common wagers are 'Big' and 'Small'.

Variants[edit]

Sic Bo Results 2019

Grand Hazard is a gambling game of English origin, also played with three dice. It is distinct from Hazard, another gambling game of English origin, played with two dice. The dice are either thrown with a cup or rolled down a chute containing a series of inclined planes ('hazard chute') that tumble the dice as they fall.[4] Threes-of-a-kind are known as 'raffles' and pay out at 18 to 1.

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Chuck-a-luck, also known as 'sweat cloth', 'chuckerluck' and birdcage,[4] is a variant in the United States, which has its origins in grand hazard. The three dice are kept in a device that resembles a wire-frame bird cage and that pivots about its centre. The dealer rotates the cage end over end, with the dice landing on the bottom. Chuck-a-luck usually features only the single-number wagers, sometimes with an additional wager for any 'triple' (all three dice showing the same number) with odds of 30 to 1 (or thereabouts). Chuck-a-luck was once common in Nevada casinos but is now rare, frequently having been replaced by sic bo tables.

See also[edit]

  • Cee-lo - a gambling game played with three six-sided dice

Notes[edit]

  1. ^Online Online Sic Bo Guide
  2. ^'Rules and Strategies for Sic Bo'. Retrieved December 3, 2010.
  3. ^'Sic Bo Rules – Learn How to Play'. Retrieved 2021-02-09.
  4. ^ abThe Official World Encyclopaedia of Sports and Games 1979 Diagram Group p 128

References[edit]

Super Sic Bo Results

Regulation in the United Kingdom

Regulation in New Zealand

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